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Jamb Mathematics - Lesson Notes on Euclidean Geometry for UTME Candidate

Feb 12 2025 10:05 PM

Osason

Jamb Updates

Euclidean Geometry | Jamb Mathematics

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Hello! As you prepare for your examination on Euclidean Geometry, focus on understanding fundamental concepts such as points, lines, angles, triangles, circles, and their properties. Be sure to practice theorem applications, problem-solving techniques, and geometric proofs to strengthen your grasp of the topic.
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Are you preparing for your JAMB Mathematics exam and feeling a bit uncertain about how to approach the topic of Euclidean Geometry? Don’t worry—you’re in the right place! This lesson is here to break it down in a simple, clear, and engaging way, helping you build the strong foundation you need to succeed. Whether you're struggling with complex questions or just seeking a quick refresher, this guide will boost your understanding and confidence. Let’s tackle Euclidean Geometry together and move one step closer to achieving your exam success! Blissful learning.
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Calculation problem involving lines and angles

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1. Sum of Angles in a Triangle
Question: In a triangle, two angles measure 5050^\circ and 6060^\circ. Find the third angle.
Solution:
The sum of the angles in a triangle is 180180^\circ.
Let the third angle be xx:
50+60+x=18050^\circ + 60^\circ + x = 180^\circ
110+x=180110^\circ + x = 180^\circ
x=180110=70x = 180^\circ - 110^\circ = 70^\circ.
Thus, the third angle is 7070^\circ.

2. Complementary Angles
Question: If one angle measures 3535^\circ, find its complement.
Solution:
Complementary angles sum to 9090^\circ.
Let the unknown angle be xx:
35+x=9035^\circ + x = 90^\circ
x=9035=55x = 90^\circ - 35^\circ = 55^\circ.
Thus, the complement is 5555^\circ.

3. Supplementary Angles
Question: If one angle is 110110^\circ, find its supplement.
Solution:
Supplementary angles sum to 180180^\circ.
Let the unknown angle be xx:
110+x=180110^\circ + x = 180^\circ
x=180110=70x = 180^\circ - 110^\circ = 70^\circ.
Thus, the supplement is 7070^\circ.

4. Adjacent Angles
Question: Two adjacent angles share a common side. If one angle is 6565^\circ and the other is 2525^\circ, find their sum.
Solution:
Sum of adjacent angles = 65+25=9065^\circ + 25^\circ = 90^\circ.
Thus, the total is 9090^\circ.

5. Vertically Opposite Angles
Question: Two vertically opposite angles are equal. If one measures 7272^\circ, find the other.
Solution:
Vertically opposite angles are equal:
Thus, the second angle is also 7272^\circ.

6. Parallel Lines and Transversals
Question: In a pair of parallel lines cut by a transversal, one alternate interior angle measures 4040^\circ. Find the other alternate interior angle.
Solution:
Alternate interior angles are equal.
Thus, the other angle is also 4040^\circ.

7. Corresponding Angles
Question: In a set of parallel lines cut by a transversal, one corresponding angle measures 5050^\circ. Find its corresponding angle.
Solution:
Corresponding angles are equal.
Thus, the angle is also 5050^\circ.

8. Perpendicular Lines
Question: If two lines are perpendicular, what is the measure of the angle they form?
Solution:
Perpendicular lines form a right angle, which is 9090^\circ.

9. Interior Angles of a Quadrilateral
Question: The angles of a quadrilateral are 8080^\circ, 9595^\circ, and 100100^\circ. Find the fourth angle.
Solution:
Sum of angles in a quadrilateral = 360360^\circ.
Let the unknown angle be xx:
80+95+100+x=36080^\circ + 95^\circ + 100^\circ + x = 360^\circ
275+x=360275^\circ + x = 360^\circ
x=360275=85x = 360^\circ - 275^\circ = 85^\circ.
Thus, the missing angle is 8585^\circ.

10. Angle Between Two Perpendicular Bisectors
Question: Two perpendicular bisectors intersect. What is the angle between them?
Solution:
Since they are perpendicular, they form a 9090^\circ angle.

11. Sum of Exterior Angles of a Polygon
Question: What is the sum of the exterior angles of any polygon?
Solution:
The sum of the exterior angles of any polygon is always 360360^\circ.

12. Right Triangle Complementary Angles
Question: One acute angle of a right triangle is 3737^\circ. Find the other acute angle.
Solution:
In a right triangle, the two acute angles sum to 9090^\circ.
Let the unknown angle be xx:
37+x=9037^\circ + x = 90^\circ
x=9037=53x = 90^\circ - 37^\circ = 53^\circ.
Thus, the missing angle is 5353^\circ.

13. Exterior Angle Theorem
Question: In a triangle, one exterior angle measures 110110^\circ. If one of the opposite interior angles is 4040^\circ, find the other interior angle.
Solution:
Exterior angle theorem states:
110=40+x110^\circ = 40^\circ + x
x=11040=70x = 110^\circ - 40^\circ = 70^\circ.
Thus, the missing interior angle is 7070^\circ.

14. Reflex Angle
Question: Find the reflex angle of 120120^\circ.
Solution:
Reflex angle = 360120=240360^\circ - 120^\circ = 240^\circ.
Thus, the reflex angle is 240240^\circ.

15. Bisected Angle
Question: An angle of 8080^\circ is bisected. Find each resulting angle.
Solution:
Each angle = 802=40\frac{80^\circ}{2} = 40^\circ.
Thus, each angle is 4040^\circ.

16. Parallel Line Alternate Exterior Angles
Question: If an alternate exterior angle measures 130130^\circ, find its pair.
Solution:
Alternate exterior angles are equal.
Thus, the other angle is also 130130^\circ.

17. Linear Pair
Question: Two angles form a linear pair. If one angle is 112112^\circ, find the other.
Solution:
Linear pairs sum to 180180^\circ.
Let the unknown angle be xx:
112+x=180112^\circ + x = 180^\circ
x=180112=68x = 180^\circ - 112^\circ = 68^\circ.
Thus, the other angle is 6868^\circ.

18. Angle in an Equilateral Triangle
Question: Find each angle in an equilateral triangle.
Solution:
Each angle in an equilateral triangle is 6060^\circ.

19. Opposite Angles in a Parallelogram
Question: If one angle in a parallelogram is 7575^\circ, find its opposite angle.
Solution:
Opposite angles in a parallelogram are equal.
Thus, the opposite angle is also 7575^\circ.

20. Sum of Interior Angles of a Hexagon
Question: Find the sum of the interior angles of a hexagon.
Solution:
Sum of interior angles of an nn-sided polygon = (n2)×180(n - 2) \times 180^\circ.
For a hexagon (n=6n = 6):
(62)×180=4×180=720(6 - 2) \times 180^\circ = 4 \times 180^\circ = 720^\circ.
Thus, the sum is 720720^\circ.

Calculation problem invloving polygons

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1. Sum of Interior Angles of a Triangle
Question: Find the sum of the interior angles of a triangle.
Solution:
The formula for the sum of interior angles of a polygon is:
S=(n2)×180S = (n - 2) \times 180^\circ, where nn is the number of sides.
For a triangle (n=3n = 3):
S=(32)×180=180S = (3 - 2) \times 180^\circ = 180^\circ.
Thus, the sum of the interior angles is 180180^\circ.

2. Sum of Interior Angles of a Quadrilateral
Question: Find the sum of the interior angles of a quadrilateral.
Solution:
S=(42)×180=2×180=360S = (4 - 2) \times 180^\circ = 2 \times 180^\circ = 360^\circ.
Thus, the sum is 360360^\circ.

3. Sum of Interior Angles of a Pentagon
Question: Find the sum of the interior angles of a pentagon.
Solution:
S=(52)×180=3×180=540S = (5 - 2) \times 180^\circ = 3 \times 180^\circ = 540^\circ.
Thus, the sum is 540540^\circ.

4. Sum of Interior Angles of a Hexagon
Question: Find the sum of the interior angles of a hexagon.
Solution:
S=(62)×180=4×180=720S = (6 - 2) \times 180^\circ = 4 \times 180^\circ = 720^\circ.
Thus, the sum is 720720^\circ.

5. Sum of Interior Angles of an Octagon
Question: Find the sum of the interior angles of an octagon.
Solution:
S=(82)×180=6×180=1080S = (8 - 2) \times 180^\circ = 6 \times 180^\circ = 1080^\circ.
Thus, the sum is 10801080^\circ.

6. Measure of One Interior Angle of a Regular Pentagon
Question: Find the measure of one interior angle of a regular pentagon.
Solution:
A regular polygon has all angles equal. The formula for one interior angle is:
θ=Sn=5405=108\theta = \frac{S}{n} = \frac{540^\circ}{5} = 108^\circ.
Thus, each interior angle is 108108^\circ.

7. Measure of One Interior Angle of a Regular Hexagon
Question: Find the measure of one interior angle of a regular hexagon.
Solution:
θ=7206=120\theta = \frac{720^\circ}{6} = 120^\circ.
Thus, each interior angle is 120120^\circ.

8. Measure of One Interior Angle of a Regular Octagon
Question: Find the measure of one interior angle of a regular octagon.
Solution:
θ=10808=135\theta = \frac{1080^\circ}{8} = 135^\circ.
Thus, each interior angle is 135135^\circ.

9. Sum of Exterior Angles of Any Polygon
Question: What is the sum of the exterior angles of any polygon?
Solution:
For any polygon, the sum of exterior angles is always 360360^\circ.

10. Measure of One Exterior Angle of a Regular Pentagon
Question: Find the measure of one exterior angle of a regular pentagon.
Solution:
θext=3605=72\theta_{\text{ext}} = \frac{360^\circ}{5} = 72^\circ.
Thus, each exterior angle is 7272^\circ.

11. Measure of One Exterior Angle of a Regular Hexagon
Question: Find the measure of one exterior angle of a regular hexagon.
Solution:
θext=3606=60\theta_{\text{ext}} = \frac{360^\circ}{6} = 60^\circ.
Thus, each exterior angle is 6060^\circ.

12. Measure of One Exterior Angle of a Regular Octagon
Question: Find the measure of one exterior angle of a regular octagon.
Solution:
θext=3608=45\theta_{\text{ext}} = \frac{360^\circ}{8} = 45^\circ.
Thus, each exterior angle is 4545^\circ.

13. Number of Sides Given Interior Angle
Question: A regular polygon has each interior angle measuring 140140^\circ. Find the number of sides.
Solution:
Using the formula:
θint+θext=180\theta_{\text{int}} + \theta_{\text{ext}} = 180^\circ.
140+θext=180140^\circ + \theta_{\text{ext}} = 180^\circ.
θext=40\theta_{\text{ext}} = 40^\circ.
Now, using θext=360n\theta_{\text{ext}} = \frac{360^\circ}{n}:
40=360n40^\circ = \frac{360^\circ}{n}.
n=36040=9n = \frac{360}{40} = 9.
Thus, the polygon has 9 sides.

14. Number of Diagonals in a Pentagon
Question: Find the number of diagonals in a pentagon.
Solution:
The formula for the number of diagonals in a polygon is:
D=n(n3)2D = \frac{n(n - 3)}{2}.
For a pentagon (n=5n = 5):
D=5(53)2=5(2)2=5D = \frac{5(5 - 3)}{2} = \frac{5(2)}{2} = 5.
Thus, a pentagon has 5 diagonals.

15. Number of Diagonals in a Hexagon
Question: Find the number of diagonals in a hexagon.
Solution:
D=6(63)2=6(3)2=9D = \frac{6(6 - 3)}{2} = \frac{6(3)}{2} = 9.
Thus, a hexagon has 9 diagonals.

16. Number of Diagonals in an Octagon
Question: Find the number of diagonals in an octagon.
Solution:
D=8(83)2=8(5)2=20D = \frac{8(8 - 3)}{2} = \frac{8(5)}{2} = 20.
Thus, an octagon has 20 diagonals.

17. Find a Missing Interior Angle in a Quadrilateral
Question: A quadrilateral has three angles measuring 9090^\circ, 8585^\circ, and 7575^\circ. Find the fourth angle.
Solution:
Sum of interior angles = 360360^\circ.
90+85+75+x=36090^\circ + 85^\circ + 75^\circ + x = 360^\circ.
x=360250=110x = 360^\circ - 250^\circ = 110^\circ.
Thus, the missing angle is 110110^\circ.

18. Find a Missing Interior Angle in a Pentagon
Question: A pentagon has four angles measuring 100100^\circ, 120120^\circ, 9595^\circ, and 8585^\circ. Find the fifth angle.
Solution:
Sum of interior angles = 540540^\circ.
100+120+95+85+x=540100^\circ + 120^\circ + 95^\circ + 85^\circ + x = 540^\circ.
x=540400=140x = 540^\circ - 400^\circ = 140^\circ.
Thus, the missing angle is 140140^\circ.

19. Relationship Between Interior and Exterior Angles
Question: Find the relationship between an interior and exterior angle in any polygon.
Solution:
Each interior and exterior angle are supplementary:
θint+θext=180\theta_{\text{int}} + \theta_{\text{ext}} = 180^\circ.

20. Regular vs Irregular Polygons
Question: How do you differentiate a regular polygon from an irregular polygon?
Solution:
A regular polygon has equal sides and angles, whereas an irregular polygon has unequal sides or angles.

Calculation problems involving angles using circle theorems

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Here are 20 unique calculation problems involving angles using Circle Theorems, with step-by-step solutions following your LaTeX formatting instructions.

1. Angle in a Semicircle
Question: A triangle is inscribed in a semicircle where the diameter is the base. If one angle of the triangle is xx^\circ, find xx.
Solution:
The angle in a semicircle theorem states that an angle subtended by a semicircle is always 9090^\circ.
Thus, x=90x = 90^\circ.

2. Angles in the Same Segment
Question: In a circle, two angles subtended by the same chord on the same segment are 4545^\circ and yy^\circ. Find yy.
Solution:
Angles in the same segment are equal.
Thus, y=45y = 45^\circ.

3. Angle at the Center vs Angle at the Circumference
Question: An angle subtended at the center of a circle is 120120^\circ. Find the angle subtended by the same arc at the circumference.
Solution:
The angle at the center is twice the angle at the circumference.
Let the angle at the circumference be xx:
x=1202=60x = \frac{120^\circ}{2} = 60^\circ.
Thus, the angle is 6060^\circ.

4. Alternate Segment Theorem
Question: A tangent to a circle makes an angle of 4040^\circ with a chord. Find the angle in the alternate segment.
Solution:
By the alternate segment theorem, the angle in the alternate segment is equal to the angle between the tangent and the chord.
Thus, the angle is 4040^\circ.

5. Opposite Angles in a Cyclic Quadrilateral
Question: A cyclic quadrilateral has one angle measuring 110110^\circ. Find its opposite angle.
Solution:
The sum of opposite angles in a cyclic quadrilateral is 180180^\circ.
Let the unknown angle be xx:
110+x=180110^\circ + x = 180^\circ
x=180110=70x = 180^\circ - 110^\circ = 70^\circ.
Thus, the opposite angle is 7070^\circ.

6. Cyclic Quadrilateral Angle
Question: A cyclic quadrilateral has angles measuring 8080^\circ, xx^\circ, 9595^\circ, and yy^\circ. Find xx and yy.
Solution:
Opposite angles in a cyclic quadrilateral sum to 180180^\circ.
For xx:
x+80=180x + 80^\circ = 180^\circ
x=100x = 100^\circ.
For yy:
y+95=180y + 95^\circ = 180^\circ
y=85y = 85^\circ.
Thus, x=100x = 100^\circ and y=85y = 85^\circ.

7. Tangent and Radius
Question: A radius of a circle meets a tangent at a point. What is the angle between them?
Solution:
The tangent and radius theorem states that the radius meets the tangent at 9090^\circ.

8. Perpendicular from the Center
Question: A perpendicular is drawn from the center of a circle to a chord. How does it affect the chord?
Solution:
The perpendicular from the center to a chord bisects the chord.

9. Angle Between Two Tangents
Question: Two tangents are drawn to a circle from an external point. If the angle between them is 5050^\circ, find the angle subtended at the center.
Solution:
The external angle is half the angle subtended at the center.
Let the angle at the center be xx:
x=2×50=100x = 2 \times 50^\circ = 100^\circ.
Thus, the angle is 100100^\circ.

10. Chord and Perpendicular Bisector
Question: A chord is bisected by a perpendicular from the center. If one half of the chord is 55 cm and the perpendicular is 1212 cm, find the radius of the circle.
Solution:
Using Pythagoras' Theorem:
r2=122+52r^2 = 12^2 + 5^2
r2=144+25r^2 = 144 + 25
r=169=13r = \sqrt{169} = 13 cm.
Thus, the radius is 1313 cm.

11. Length of a Tangent
Question: A circle has a radius of 77 cm, and an external point is 2525 cm from the center. Find the length of the tangent.
Solution:
Using Pythagoras' theorem:
t2+72=252t^2 + 7^2 = 25^2
t2+49=625t^2 + 49 = 625
t2=576t^2 = 576
t=576=24t = \sqrt{576} = 24 cm.
Thus, the tangent length is 2424 cm.

12. Two Tangents from a Point
Question: Two tangents from an external point to a circle are equal. One is 1010 cm long. Find the other.
Solution:
By the two tangents theorem, both tangents from an external point are equal.
Thus, the second tangent is 1010 cm.

13. Exterior Angle of a Cyclic Quadrilateral
Question: An exterior angle of a cyclic quadrilateral is 7575^\circ. Find the interior opposite angle.
Solution:
An exterior angle is equal to the opposite interior angle in a cyclic quadrilateral.
Thus, the opposite angle is 7575^\circ.

14. Angle in the Major Segment
Question: An angle in a major segment is given as 120120^\circ. Find the angle in the minor segment.
Solution:
Angles in the same segment add up to 180180^\circ.
Thus, the minor segment angle is 6060^\circ.

15. Interior Angle Between Two Chords
Question: Two chords intersect inside a circle at an angle of 130130^\circ. Find the two exterior angles.
Solution:
The exterior angles are supplementary to the interior angle.
180130=50180^\circ - 130^\circ = 50^\circ.
Thus, each exterior angle is 5050^\circ.

16. Angle in an Inscribed Equilateral Triangle
Question: A circle has an equilateral triangle inscribed in it. Find each angle.
Solution:
Each angle in an equilateral triangle is 6060^\circ.

17. Two Chords Intersecting Inside a Circle
Question: Two chords intersect at a point inside a circle forming angles of 4040^\circ and xx^\circ. Find xx.
Solution:
Opposite angles are equal, so x=40x = 40^\circ.

18. Reflex Angle at the Center
Question: If an angle subtended at the center is 100100^\circ, find its reflex angle.
Solution:
Reflex angle = 360100=260360^\circ - 100^\circ = 260^\circ.

19. Alternate Segment Angle in a Tangent-Chord
Question: A tangent to a circle forms a 5858^\circ angle with a chord. Find the angle in the alternate segment.
Solution:
By the alternate segment theorem, the angle in the alternate segment is also 5858^\circ.

20. Finding the Angle Between Two Radii
Question: Two radii form an isosceles triangle in a circle. If the base angle is 5050^\circ, find the angle at the center.
Solution:
Using the sum of angles in a triangle:
x+50+50=180x + 50^\circ + 50^\circ = 180^\circ
x=180100=80x = 180^\circ - 100^\circ = 80^\circ.
Thus, the angle at the center is 8080^\circ.
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Thank you for taking the time to read my blog post! Your interest and engagement mean so much to me, and I hope the content provided valuable insights and sparked your curiosity. Your journey as a student is inspiring, and it’s my goal to contribute to your growth and success.
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